X^2/3+21p=100

Solution for X^2/3+21p=100 equation:

X^2/3+21X=100

We move all terms to the left:

X^2/3+21X-(100)=0

We multiply all the terms by the denominator


X^2+21X*3-100*3=0

We add all the numbers together, and all the variables

X^2+21X*3-300=0

Wy multiply elements

X^2+63X-300=0

a = 1; b = 63; c = -300;
Δ = b2-4ac
Δ = 632-4·1·(-300)
Δ = 5169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(63)-\sqrt{5169}}{2*1}=\frac{-63-\sqrt{5169}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(63)+\sqrt{5169}}{2*1}=\frac{-63+\sqrt{5169}}{2}
$